4x^2+60x+224=0

Solution for 4x^2+60x+224=0 equation:

4x^2+60x+224=0

a = 4; b = 60; c = +224;
Δ = b2-4ac
Δ = 602-4·4·224
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4}{2*4}=\frac{-56}{8}
=-7
$